I'm getting in 5 young starts of "Sioux" that are only going to be about 10" tall. When it cools off in the fall I'll be planting them on the side of my yard in a row in full sun (I have a 145' border there so no worries about space). Funny thing is I had two that were over 8' tall and I gave them to friends because at the time I didn't have a place I wanted to keep them permanently, lol. Well, they had suckers I wasn't aware of and I kept two of the suckers - which grow at an average rate of 18" a year - they are 3' and 4' tall now and won't be a part of the new row I have planned. I'll be centering the new young 10" trees in the length of the 145' length of my side yard - my question is how far apart would you plant them from each other? "Sioux" doesn't get very big, and I think I might prefer if the crowns didn't touch (or barely did) years from now when they are mature. I've read everything for 8' to 16' wide at maturity for "Sioux", which I guess depends largely on zone and soil/growing conditions. I was thinking maybe centering them at 8 - 10'? I'm in z6b and crape myrtles thrive here. Thanks!
